Solve for B (complex solution)
\left\{\begin{matrix}B\neq 0\text{, }&\left(W=0\text{ or }L=0\right)\text{ and }D=0\\B=\frac{LW}{15D^{2}}\text{, }&\left(|\frac{arg(D^{2})}{2}-arg(D)|<\pi \text{ or }arg(D)\geq \pi \right)\text{ and }L\neq 0\text{ and }W\neq 0\text{ and }D\neq 0\end{matrix}\right.
Solve for B
\left\{\begin{matrix}B\neq 0\text{, }&\left(L=0\text{ or }W=0\right)\text{ and }D=0\\B=\frac{LW}{15D^{2}}\text{, }&L\neq 0\text{ and }W\neq 0\text{ and }D\neq 0\end{matrix}\right.
Solve for D (complex solution)
D=-\frac{B^{-\frac{1}{2}}\sqrt{L}\sqrt{15W}}{15}
D=\frac{B^{-\frac{1}{2}}\sqrt{L}\sqrt{15W}}{15}\text{, }B\neq 0
Solve for D
D=\frac{\sqrt{\frac{15LW}{B}}}{15}
D=-\frac{\sqrt{\frac{15LW}{B}}}{15}\text{, }\left(L\leq 0\text{ and }W\leq 0\text{ and }B>0\right)\text{ or }\left(W\geq 0\text{ and }L\geq 0\text{ and }B>0\right)\text{ or }\left(W\leq 0\text{ and }L\geq 0\text{ and }B<0\right)\text{ or }\left(L\leq 0\text{ and }W\geq 0\text{ and }B<0\right)
Quiz
Linear Equation
5 problems similar to:
( D ) ^ { 2 } = ( \sqrt { \frac { W L } { 15 B } } ) ^ { 2 }
Share
Copied to clipboard
D^{2}=\frac{WL}{15B}
Calculate \sqrt{\frac{WL}{15B}} to the power of 2 and get \frac{WL}{15B}.
\frac{WL}{15B}=D^{2}
Swap sides so that all variable terms are on the left hand side.
WL=15BD^{2}
Variable B cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 15B.
LW=15BD^{2}
Reorder the terms.
15BD^{2}=LW
Swap sides so that all variable terms are on the left hand side.
15D^{2}B=LW
The equation is in standard form.
\frac{15D^{2}B}{15D^{2}}=\frac{LW}{15D^{2}}
Divide both sides by 15D^{2}.
B=\frac{LW}{15D^{2}}
Dividing by 15D^{2} undoes the multiplication by 15D^{2}.
B=\frac{LW}{15D^{2}}\text{, }B\neq 0
Variable B cannot be equal to 0.
D^{2}=\frac{WL}{15B}
Calculate \sqrt{\frac{WL}{15B}} to the power of 2 and get \frac{WL}{15B}.
\frac{WL}{15B}=D^{2}
Swap sides so that all variable terms are on the left hand side.
WL=15BD^{2}
Variable B cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 15B.
LW=15BD^{2}
Reorder the terms.
15BD^{2}=LW
Swap sides so that all variable terms are on the left hand side.
15D^{2}B=LW
The equation is in standard form.
\frac{15D^{2}B}{15D^{2}}=\frac{LW}{15D^{2}}
Divide both sides by 15D^{2}.
B=\frac{LW}{15D^{2}}
Dividing by 15D^{2} undoes the multiplication by 15D^{2}.
B=\frac{LW}{15D^{2}}\text{, }B\neq 0
Variable B cannot be equal to 0.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}