Solve (D):2x-y+1=0

$$( D ) : 2 x - y + 1 = 0$$

Solve for D (complex solution)

$$\left\{\begin{matrix}D=-\frac{2\left(1-y\right)}{x}\text{, }&x\neq 0\\D\in \mathrm{C}\text{, }&y=1\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$Dx-2y+2=0$$

Add 2y to both sides. Anything plus zero gives itself.

$$Dx+2=2y$$

Subtract 2 from both sides.

$$Dx=2y-2$$

The equation is in standard form.

$$xD=2y-2$$

Divide both sides by x.

$$\frac{xD}{x}=\frac{2y-2}{x}$$

Dividing by x undoes the multiplication by x.

$$D=\frac{2y-2}{x}$$

Divide -2+2y by x.

$$D=\frac{2\left(y-1\right)}{x}$$

Solve for x (complex solution)

$$\left\{\begin{matrix}x=-\frac{2\left(1-y\right)}{D}\text{, }&D\neq 0\\x\in \mathrm{C}\text{, }&y=1\text{ and }D=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$Dx-2y+2=0$$

Add 2y to both sides. Anything plus zero gives itself.

$$Dx+2=2y$$

Subtract 2 from both sides.

$$Dx=2y-2$$

Divide both sides by D.

$$\frac{Dx}{D}=\frac{2y-2}{D}$$

Dividing by D undoes the multiplication by D.

$$x=\frac{2y-2}{D}$$

Divide -2+2y by D.

$$x=\frac{2\left(y-1\right)}{D}$$

Solve for D

$$\left\{\begin{matrix}D=-\frac{2\left(1-y\right)}{x}\text{, }&x\neq 0\\D\in \mathrm{R}\text{, }&y=1\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$Dx-2y+2=0$$

Add 2y to both sides. Anything plus zero gives itself.

$$Dx+2=2y$$

Subtract 2 from both sides.

$$Dx=2y-2$$

The equation is in standard form.

$$xD=2y-2$$

Divide both sides by x.

$$\frac{xD}{x}=\frac{2y-2}{x}$$

Dividing by x undoes the multiplication by x.

$$D=\frac{2y-2}{x}$$

Divide -2+2y by x.

$$D=\frac{2\left(y-1\right)}{x}$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{2\left(1-y\right)}{D}\text{, }&D\neq 0\\x\in \mathrm{R}\text{, }&y=1\text{ and }D=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$Dx-2y+2=0$$

Add 2y to both sides. Anything plus zero gives itself.

$$Dx+2=2y$$

Subtract 2 from both sides.

$$Dx=2y-2$$

Divide both sides by D.

$$\frac{Dx}{D}=\frac{2y-2}{D}$$

Dividing by D undoes the multiplication by D.

$$x=\frac{2y-2}{D}$$

Divide -2+2y by D.

$$x=\frac{2\left(y-1\right)}{D}$$