Solve (B)^2=(3-1)^2+(9-4)^2

$$( B ) ^ { 2 } = ( 3 - 1 ) ^ { 2 } + ( 9 - 4 ) ^ { 2 }$$

Solve for B

$$B=\sqrt{29}\approx 5.385164807$$

$$B=-\sqrt{29}\approx -5.385164807$$

Steps by Finding Square Root

Subtract 1 from 3 to get 2.

$$B^{2}=2^{2}+\left(9-4\right)^{2}$$

Calculate 2 to the power of 2 and get 4.

$$B^{2}=4+\left(9-4\right)^{2}$$

Subtract 4 from 9 to get 5.

$$B^{2}=4+5^{2}$$

Calculate 5 to the power of 2 and get 25.

$$B^{2}=4+25$$

Add 4 and 25 to get 29.

$$B^{2}=29$$

Take the square root of both sides of the equation.

$$B=\sqrt{29} B=-\sqrt{29}$$

Steps Using the Quadratic Formula

Subtract 1 from 3 to get 2.

$$B^{2}=2^{2}+\left(9-4\right)^{2}$$

Calculate 2 to the power of 2 and get 4.

$$B^{2}=4+\left(9-4\right)^{2}$$

Subtract 4 from 9 to get 5.

$$B^{2}=4+5^{2}$$

Calculate 5 to the power of 2 and get 25.

$$B^{2}=4+25$$

Add 4 and 25 to get 29.

$$B^{2}=29$$

Subtract 29 from both sides.

$$B^{2}-29=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -29 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$B=\frac{0±\sqrt{0^{2}-4\left(-29\right)}}{2}$$

Square 0.

$$B=\frac{0±\sqrt{-4\left(-29\right)}}{2}$$

Multiply -4 times -29.

$$B=\frac{0±\sqrt{116}}{2}$$

Take the square root of 116.

$$B=\frac{0±2\sqrt{29}}{2}$$

Now solve the equation B=\frac{0±2\sqrt{29}}{2} when ± is plus.

$$B=\sqrt{29}$$

Now solve the equation B=\frac{0±2\sqrt{29}}{2} when ± is minus.

$$B=-\sqrt{29}$$

The equation is now solved.

$$B=\sqrt{29} B=-\sqrt{29}$$