Solve (9x+7)^2-36=0

$$( 9 x + 7 ) ^ { 2 } - 36 = 0$$

Solve for x

$$x=-\frac{1}{9}\approx -0.111111111$$

$$x = -\frac{13}{9} = -1\frac{4}{9} \approx -1.444444444$$

Steps by Finding Square Root

Add 36 to both sides of the equation.

$$\left(9x+7\right)^{2}-36+36=36$$

Subtracting 36 from itself leaves 0.

$$\left(9x+7\right)^{2}=36$$

Take the square root of both sides of the equation.

$$9x+7=6 9x+7=-6$$

Subtract 7 from both sides of the equation.

$$9x+7-7=6-7 9x+7-7=-6-7$$

Subtracting 7 from itself leaves 0.

$$9x=6-7 9x=-6-7$$

Subtract 7 from 6.

$$9x=-1$$

Subtract 7 from -6.

$$9x=-13$$

Divide both sides by 9.

$$\frac{9x}{9}=-\frac{1}{9} \frac{9x}{9}=-\frac{13}{9}$$

Dividing by 9 undoes the multiplication by 9.

$$x=-\frac{1}{9} x=-\frac{13}{9}$$