Solve (9x+25)^2=75

$$( 9 x + 25 ) ^ { 2 } = 75$$

Solve for x

$$x=\frac{5\sqrt{3}-25}{9}\approx -1.815527329$$

$$x=\frac{-5\sqrt{3}-25}{9}\approx -3.740028226$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$9x+25=5\sqrt{3} 9x+25=-5\sqrt{3}$$

Subtract 25 from both sides of the equation.

$$9x+25-25=5\sqrt{3}-25 9x+25-25=-5\sqrt{3}-25$$

Subtracting 25 from itself leaves 0.

$$9x=5\sqrt{3}-25 9x=-5\sqrt{3}-25$$

Subtract 25 from 5\sqrt{3}.

$$9x=5\sqrt{3}-25$$

Subtract 25 from -5\sqrt{3}.

$$9x=-5\sqrt{3}-25$$

Divide both sides by 9.

$$\frac{9x}{9}=\frac{5\sqrt{3}-25}{9} \frac{9x}{9}=\frac{-5\sqrt{3}-25}{9}$$

Dividing by 9 undoes the multiplication by 9.

$$x=\frac{5\sqrt{3}-25}{9} x=\frac{-5\sqrt{3}-25}{9}$$