Solve (9u+8)+(u+5)

$$( 9 u + 8 ) + ( u + 5 )$$

Evaluate

$$10u+13$$

Solution Steps

Combine 9u and u to get 10u.

$$10u+8+5$$

Add 8 and 5 to get 13.

$$10u+13$$

Differentiate w.r.t. u

$$10$$

Steps Using Derivative Rule for Sum

Combine 9u and u to get 10u.

$$\frac{\mathrm{d}}{\mathrm{d}u}(10u+8+5)$$

Add 8 and 5 to get 13.

$$\frac{\mathrm{d}}{\mathrm{d}u}(10u+13)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$10u^{1-1}$$

Subtract 1 from 1.

$$10u^{0}$$

For any term t except 0, t^{0}=1.

$$10\times 1$$

For any term t, t\times 1=t and 1t=t.

$$10$$