Solve for b
b=\frac{9t}{2}-4
Solve for t
t=\frac{2\left(b+4\right)}{9}
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-2b=8-9t
Subtract 9t from both sides.
\frac{-2b}{-2}=\frac{8-9t}{-2}
Divide both sides by -2.
b=\frac{8-9t}{-2}
Dividing by -2 undoes the multiplication by -2.
b=\frac{9t}{2}-4
Divide 8-9t by -2.
9t=8+2b
Add 2b to both sides.
9t=2b+8
The equation is in standard form.
\frac{9t}{9}=\frac{2b+8}{9}
Divide both sides by 9.
t=\frac{2b+8}{9}
Dividing by 9 undoes the multiplication by 9.
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