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729b^{3}+1215b^{2}+675b+125-27
Use binomial theorem \left(p+q\right)^{3}=p^{3}+3p^{2}q+3pq^{2}+q^{3} to expand \left(9b+5\right)^{3}.
729b^{3}+1215b^{2}+675b+98
Subtract 27 from 125 to get 98.
729b^{3}+1215b^{2}+675b+125-27
Use binomial theorem \left(p+q\right)^{3}=p^{3}+3p^{2}q+3pq^{2}+q^{3} to expand \left(9b+5\right)^{3}.
729b^{3}+1215b^{2}+675b+98
Subtract 27 from 125 to get 98.