Solve (9*6/x-9)+(2*0)+(3*(-3)+(7*-5)

$$( 9 \cdot \frac { 6 } { x } - 9 ) + ( 2 \cdot 0 ) + ( 3 \cdot ( - 3 ) + ( 7 \cdot - 5 )$$

Evaluate

$$-53+\frac{54}{x}$$

Short Solution Steps

Multiply 2 and 0 to get 0. Multiply 3 and -3 to get -9. Multiply 7 and -5 to get -35.

$$9\times \frac{6}{x}-9+0-9-35$$

Express 9\times \frac{6}{x} as a single fraction.

$$\frac{9\times 6}{x}-9+0-9-35$$

Add -9 and 0 to get -9.

$$\frac{9\times 6}{x}-9-9-35$$

Subtract 9 from -9 to get -18.

$$\frac{9\times 6}{x}-18-35$$

Subtract 35 from -18 to get -53.

$$\frac{9\times 6}{x}-53$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 53 times \frac{x}{x}.

$$\frac{9\times 6}{x}-\frac{53x}{x}$$

Since \frac{9\times 6}{x} and \frac{53x}{x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9\times 6-53x}{x}$$

Do the multiplications in 9\times 6-53x.

$$\frac{54-53x}{x}$$

Factor

$$-\frac{53x-54}{x}$$