Solve (9^2:5^0+1^2+sqrt{100}-2)*10^3=

$$( 9 ^ { 2 } : 5 ^ { 0 } + 1 ^ { 2 } + \sqrt { 100 } - 2 ) \cdot 10 ^ { 3 } =$$

Evaluate

$$90000$$

Solution Steps

Calculate 9 to the power of 2 and get 81.

$$\left(\frac{81}{5^{0}}+1^{2}+\sqrt{100}-2\right)\times 10^{3}$$

Calculate 5 to the power of 0 and get 1.

$$\left(\frac{81}{1}+1^{2}+\sqrt{100}-2\right)\times 10^{3}$$

Anything divided by one gives itself.

$$\left(81+1^{2}+\sqrt{100}-2\right)\times 10^{3}$$

Calculate 1 to the power of 2 and get 1.

$$\left(81+1+\sqrt{100}-2\right)\times 10^{3}$$

Add 81 and 1 to get 82.

$$\left(82+\sqrt{100}-2\right)\times 10^{3}$$

Calculate the square root of 100 and get 10.

$$\left(82+10-2\right)\times 10^{3}$$

Add 82 and 10 to get 92.

$$\left(92-2\right)\times 10^{3}$$

Subtract 2 from 92 to get 90.

$$90\times 10^{3}$$

Calculate 10 to the power of 3 and get 1000.

$$90\times 1000$$

Multiply 90 and 1000 to get 90000.

$$90000$$

Factor

$$2^{4}\times 3^{2}\times 5^{4}$$