Solve (8-x)^2=x^2+4

$$( 8 - x ) ^ { 2 } = x ^ { 2 } + 4$$

Solve for x

$$x = \frac{15}{4} = 3\frac{3}{4} = 3.75$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(8-x\right)^{2}.

$$64-16x+x^{2}=x^{2}+4$$

Subtract x^{2} from both sides.

$$64-16x+x^{2}-x^{2}=4$$

Combine x^{2} and -x^{2} to get 0.

$$64-16x=4$$

Subtract 64 from both sides.

$$-16x=4-64$$

Subtract 64 from 4 to get -60.

$$-16x=-60$$

Divide both sides by -16.

$$x=\frac{-60}{-16}$$

Reduce the fraction \frac{-60}{-16} to lowest terms by extracting and canceling out -4.

$$x=\frac{15}{4}$$