Solve (8-5)^3+2(4^2-13)-7(6^2-30)

$$( 8 - 5 ) ^ { 3 } + 2 ( 4 ^ { 2 } - 13 ) - 7 ( 6 ^ { 2 } - 30 )$$

Evaluate

$$-9$$

Solution Steps

Subtract 5 from 8 to get 3.

$$3^{3}+2\left(4^{2}-13\right)-7\left(6^{2}-30\right)$$

Calculate 3 to the power of 3 and get 27.

$$27+2\left(4^{2}-13\right)-7\left(6^{2}-30\right)$$

Calculate 4 to the power of 2 and get 16.

$$27+2\left(16-13\right)-7\left(6^{2}-30\right)$$

Subtract 13 from 16 to get 3.

$$27+2\times 3-7\left(6^{2}-30\right)$$

Multiply 2 and 3 to get 6.

$$27+6-7\left(6^{2}-30\right)$$

Add 27 and 6 to get 33.

$$33-7\left(6^{2}-30\right)$$

Calculate 6 to the power of 2 and get 36.

$$33-7\left(36-30\right)$$

Subtract 30 from 36 to get 6.

$$33-7\times 6$$

Multiply 7 and 6 to get 42.

$$33-42$$

Subtract 42 from 33 to get -9.

$$-9$$

Factor

$$-9$$