Solve (8-0)+y^2=1200

$$( 8 - 0 ) + y ^ { 2 } = 1200$$

Solve for y

$$y=2\sqrt{298}\approx 34.525353003$$

$$y=-2\sqrt{298}\approx -34.525353003$$

Steps by Finding Square Root

Subtract 0 from 8 to get 8.

$$8+y^{2}=1200$$

Subtract 8 from both sides.

$$y^{2}=1200-8$$

Subtract 8 from 1200 to get 1192.

$$y^{2}=1192$$

Take the square root of both sides of the equation.

$$y=2\sqrt{298} y=-2\sqrt{298}$$

Steps Using the Quadratic Formula

Subtract 0 from 8 to get 8.

$$8+y^{2}=1200$$

Subtract 1200 from both sides.

$$8+y^{2}-1200=0$$

Subtract 1200 from 8 to get -1192.

$$-1192+y^{2}=0$$

Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.

$$y^{2}-1192=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -1192 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{0±\sqrt{0^{2}-4\left(-1192\right)}}{2}$$

Square 0.

$$y=\frac{0±\sqrt{-4\left(-1192\right)}}{2}$$

Multiply -4 times -1192.

$$y=\frac{0±\sqrt{4768}}{2}$$

Take the square root of 4768.

$$y=\frac{0±4\sqrt{298}}{2}$$

Now solve the equation y=\frac{0±4\sqrt{298}}{2} when ± is plus.

$$y=2\sqrt{298}$$

Now solve the equation y=\frac{0±4\sqrt{298}}{2} when ± is minus.

$$y=-2\sqrt{298}$$

The equation is now solved.

$$y=2\sqrt{298} y=-2\sqrt{298}$$