Solve (8)^2-4(k)(6)>0

$$( 8 ) ^ { 2 } - 4 ( k ) ( 6 ) > 0$$

Solve for k

$$k<\frac{8}{3}$$

Solution Steps

Calculate 8 to the power of 2 and get 64.

$$64-4k\times 6>0$$

Multiply 4 and 6 to get 24.

$$64-24k>0$$

Subtract 64 from both sides. Anything subtracted from zero gives its negation.

$$-24k>-64$$

Divide both sides by -24. Since -24 is negative, the inequality direction is changed.

$$k<\frac{-64}{-24}$$

Reduce the fraction \frac{-64}{-24} to lowest terms by extracting and canceling out -8.

$$k<\frac{8}{3}$$