Solve (85/8+311/12)*18

$$( 8 \frac { 5 } { 8 } + 3 \frac { 11 } { 12 } ) \cdot 18$$

Evaluate

$$\frac{903}{4}=225.75$$

Solution Steps

Multiply 8 and 8 to get 64.

$$\left(\frac{64+5}{8}+\frac{3\times 12+11}{12}\right)\times 18$$

Add 64 and 5 to get 69.

$$\left(\frac{69}{8}+\frac{3\times 12+11}{12}\right)\times 18$$

Multiply 3 and 12 to get 36.

$$\left(\frac{69}{8}+\frac{36+11}{12}\right)\times 18$$

Add 36 and 11 to get 47.

$$\left(\frac{69}{8}+\frac{47}{12}\right)\times 18$$

Least common multiple of 8 and 12 is 24. Convert \frac{69}{8} and \frac{47}{12} to fractions with denominator 24.

$$\left(\frac{207}{24}+\frac{94}{24}\right)\times 18$$

Since \frac{207}{24} and \frac{94}{24} have the same denominator, add them by adding their numerators.

$$\frac{207+94}{24}\times 18$$

Add 207 and 94 to get 301.

$$\frac{301}{24}\times 18$$

Express \frac{301}{24}\times 18 as a single fraction.

$$\frac{301\times 18}{24}$$

Multiply 301 and 18 to get 5418.

$$\frac{5418}{24}$$

Reduce the fraction \frac{5418}{24} to lowest terms by extracting and canceling out 6.

$$\frac{903}{4}$$

Factor

$$\frac{3 \cdot 7 \cdot 43}{2 ^ {2}} = 225\frac{3}{4} = 225.75$$