Solve (8div1/2)+(1/2div8)

$$( 8 \div \frac { 1 } { 2 } ) + ( \frac { 1 } { 2 } \div 8 )$$

Evaluate

$$\frac{257}{16}=16.0625$$

Solution Steps

Divide 8 by \frac{1}{2} by multiplying 8 by the reciprocal of \frac{1}{2}.

$$8\times 2+\frac{\frac{1}{2}}{8}$$

Multiply 8 and 2 to get 16.

$$16+\frac{\frac{1}{2}}{8}$$

Express \frac{\frac{1}{2}}{8} as a single fraction.

$$16+\frac{1}{2\times 8}$$

Multiply 2 and 8 to get 16.

$$16+\frac{1}{16}$$

Convert 16 to fraction \frac{256}{16}.

$$\frac{256}{16}+\frac{1}{16}$$

Since \frac{256}{16} and \frac{1}{16} have the same denominator, add them by adding their numerators.

$$\frac{256+1}{16}$$

Add 256 and 1 to get 257.

$$\frac{257}{16}$$

Factor

$$\frac{257}{2 ^ {4}} = 16\frac{1}{16} = 16.0625$$