Solve for x
x=2
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8+x=x\times 5
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
8+x-x\times 5=0
Subtract x\times 5 from both sides.
8-4x=0
Combine x and -x\times 5 to get -4x.
-4x=-8
Subtract 8 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-8}{-4}
Divide both sides by -4.
x=2
Divide -8 by -4 to get 2.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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