Evaluate
16\sqrt{3}+67\approx 94.712812921
Expand
16 \sqrt{3} + 67 = 94.712812921
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64+16\sqrt{3}+\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(8+\sqrt{3}\right)^{2}.
64+16\sqrt{3}+3
The square of \sqrt{3} is 3.
67+16\sqrt{3}
Add 64 and 3 to get 67.
64+16\sqrt{3}+\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(8+\sqrt{3}\right)^{2}.
64+16\sqrt{3}+3
The square of \sqrt{3} is 3.
67+16\sqrt{3}
Add 64 and 3 to get 67.
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