Solve (8+3/4)div41/5=

$$( 8 + \frac { 3 } { 4 } ) \div 4 \frac { 1 } { 5 } =$$

Evaluate

$$\frac{25}{12}\approx 2.083333333$$

Solution Steps

Convert 8 to fraction \frac{32}{4}.

$$\frac{\frac{32}{4}+\frac{3}{4}}{\frac{4\times 5+1}{5}}$$

Since \frac{32}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$\frac{\frac{32+3}{4}}{\frac{4\times 5+1}{5}}$$

Add 32 and 3 to get 35.

$$\frac{\frac{35}{4}}{\frac{4\times 5+1}{5}}$$

Multiply 4 and 5 to get 20.

$$\frac{\frac{35}{4}}{\frac{20+1}{5}}$$

Add 20 and 1 to get 21.

$$\frac{\frac{35}{4}}{\frac{21}{5}}$$

Divide \frac{35}{4} by \frac{21}{5} by multiplying \frac{35}{4} by the reciprocal of \frac{21}{5}.

$$\frac{35}{4}\times \frac{5}{21}$$

Multiply \frac{35}{4} times \frac{5}{21} by multiplying numerator times numerator and denominator times denominator.

$$\frac{35\times 5}{4\times 21}$$

Do the multiplications in the fraction \frac{35\times 5}{4\times 21}.

$$\frac{175}{84}$$

Reduce the fraction \frac{175}{84} to lowest terms by extracting and canceling out 7.

$$\frac{25}{12}$$

Factor

$$\frac{5 ^ {2}}{2 ^ {2} \cdot 3} = 2\frac{1}{12} = 2.0833333333333335$$