Solve (7x^2y)(2y^3)(7xy^2)

$$( 7 x ^ { 2 } y ) ( 2 y ^ { 3 } ) ( 7 x y ^ { 2 } )$$

Evaluate

$$98x^{3}y^{6}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$7x^{3}y\times 2y^{3}\times 7y^{2}$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$7x^{3}y^{4}\times 2\times 7y^{2}$$

To multiply powers of the same base, add their exponents. Add 4 and 2 to get 6.

$$7x^{3}y^{6}\times 2\times 7$$

Multiply 7 and 2 to get 14.

$$14x^{3}y^{6}\times 7$$

Multiply 14 and 7 to get 98.

$$98x^{3}y^{6}$$

Differentiate w.r.t. x

$$294x^{2}y^{6}$$