Solve (7r^4+r^3+3r)-(3r-r^4+2r^3)

$$( 7 r ^ { 4 } + r ^ { 3 } + 3 r ) - ( 3 r - r ^ { 4 } + 2 r ^ { 3 } )$$

Evaluate

$$\left(8r-1\right)r^{3}$$

Solution Steps

To find the opposite of 3r-r^{4}+2r^{3}, find the opposite of each term.

$$7r^{4}+r^{3}+3r-3r+r^{4}-2r^{3}$$

Combine 3r and -3r to get 0.

$$7r^{4}+r^{3}+r^{4}-2r^{3}$$

Combine 7r^{4} and r^{4} to get 8r^{4}.

$$8r^{4}+r^{3}-2r^{3}$$

Combine r^{3} and -2r^{3} to get -r^{3}.

$$8r^{4}-r^{3}$$

Expand

$$8r^{4}-r^{3}$$

Solution Steps

To find the opposite of 3r-r^{4}+2r^{3}, find the opposite of each term.

$$7r^{4}+r^{3}+3r-3r+r^{4}-2r^{3}$$

Combine 3r and -3r to get 0.

$$7r^{4}+r^{3}+r^{4}-2r^{3}$$

Combine 7r^{4} and r^{4} to get 8r^{4}.

$$8r^{4}+r^{3}-2r^{3}$$

Combine r^{3} and -2r^{3} to get -r^{3}.

$$8r^{4}-r^{3}$$