Solve (7a^2b^3)(3ab^4)

$$( 7 a ^ { 2 } b ^ { 3 } ) ( 3 a b ^ { 4 } )$$

Evaluate

$$21a^{3}b^{7}$$

Steps Using Commutative Property of Multiplication

Use the rules of exponents to simplify the expression.

$$7^{1}a^{2}b^{3}\times 3^{1}a^{1}b^{4}$$

Use the Commutative Property of Multiplication.

$$7^{1}\times 3^{1}a^{2}a^{1}b^{3}b^{4}$$

To multiply powers of the same base, add their exponents.

$$7^{1}\times 3^{1}a^{2+1}b^{3+4}$$

Add the exponents 2 and 1.

$$7^{1}\times 3^{1}a^{3}b^{3+4}$$

Add the exponents 3 and 4.

$$7^{1}\times 3^{1}a^{3}b^{7}$$

Multiply 7 times 3.

$$21a^{3}b^{7}$$

Differentiate w.r.t. a

$$63a^{2}b^{7}$$