Solve (7-6y)-3y+4-4

$$( 7 - 6 y ) - 3 y + 4 - 4$$

Evaluate

$$7-9y$$

Solution Steps

Combine -6y and -3y to get -9y.

$$7-9y+4-4$$

Add 7 and 4 to get 11.

$$11-9y-4$$

Subtract 4 from 11 to get 7.

$$7-9y$$

Differentiate w.r.t. y

$$-9$$

Steps Using Derivative Rule for Sum

Combine -6y and -3y to get -9y.

$$\frac{\mathrm{d}}{\mathrm{d}y}(7-9y+4-4)$$

Add 7 and 4 to get 11.

$$\frac{\mathrm{d}}{\mathrm{d}y}(11-9y-4)$$

Subtract 4 from 11 to get 7.

$$\frac{\mathrm{d}}{\mathrm{d}y}(7-9y)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-9y^{1-1}$$

Subtract 1 from 1.

$$-9y^{0}$$

For any term t except 0, t^{0}=1.

$$-9$$