Solve (7-3*2)*15+[(2*3)^2-(3*2^2-5*2)-5^2]

$$( 7 - 3 \times 2 ) \times 15 + [ ( 2 \times 3 ) ^ { 2 } - ( 3 \times 2 ^ { 2 } - 5 \times 2 ) - 5 ^ { 2 } ]$$

Evaluate

$$24$$

Solution Steps

Multiply 3 and 2 to get 6.

$$\left(7-6\right)\times 15+\left(2\times 3\right)^{2}-\left(3\times 2^{2}-5\times 2\right)-5^{2}$$

Subtract 6 from 7 to get 1.

$$1\times 15+\left(2\times 3\right)^{2}-\left(3\times 2^{2}-5\times 2\right)-5^{2}$$

Multiply 1 and 15 to get 15.

$$15+\left(2\times 3\right)^{2}-\left(3\times 2^{2}-5\times 2\right)-5^{2}$$

Multiply 2 and 3 to get 6.

$$15+6^{2}-\left(3\times 2^{2}-5\times 2\right)-5^{2}$$

Calculate 6 to the power of 2 and get 36.

$$15+36-\left(3\times 2^{2}-5\times 2\right)-5^{2}$$

Calculate 2 to the power of 2 and get 4.

$$15+36-\left(3\times 4-5\times 2\right)-5^{2}$$

Multiply 3 and 4 to get 12.

$$15+36-\left(12-5\times 2\right)-5^{2}$$

Multiply 5 and 2 to get 10.

$$15+36-\left(12-10\right)-5^{2}$$

Subtract 10 from 12 to get 2.

$$15+36-2-5^{2}$$

Subtract 2 from 36 to get 34.

$$15+34-5^{2}$$

Calculate 5 to the power of 2 and get 25.

$$15+34-25$$

Subtract 25 from 34 to get 9.

$$15+9$$

Add 15 and 9 to get 24.

$$24$$

Factor

$$2^{3}\times 3$$