Solve (7)-7^2+2*(-3)^2+(-6)div(-1/3)^2

$$( 7 ) - 7 ^ { 2 } + 2 \times ( - 3 ) ^ { 2 } + ( - 6 ) \div ( - \frac { 1 } { 3 } ) ^ { 2 }$$

Evaluate

$$-78$$

Solution Steps

Calculate 7 to the power of 2 and get 49.

$$7-49+2\left(-3\right)^{2}+\frac{-6}{\left(-\frac{1}{3}\right)^{2}}$$

Subtract 49 from 7 to get -42.

$$-42+2\left(-3\right)^{2}+\frac{-6}{\left(-\frac{1}{3}\right)^{2}}$$

Calculate -3 to the power of 2 and get 9.

$$-42+2\times 9+\frac{-6}{\left(-\frac{1}{3}\right)^{2}}$$

Multiply 2 and 9 to get 18.

$$-42+18+\frac{-6}{\left(-\frac{1}{3}\right)^{2}}$$

Add -42 and 18 to get -24.

$$-24+\frac{-6}{\left(-\frac{1}{3}\right)^{2}}$$

Calculate -\frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$-24+\frac{-6}{\frac{1}{9}}$$

Divide -6 by \frac{1}{9} by multiplying -6 by the reciprocal of \frac{1}{9}.

$$-24-6\times 9$$

Multiply -6 and 9 to get -54.

$$-24-54$$

Subtract 54 from -24 to get -78.

$$-78$$

Factor

$$-78$$