Solve (7)^3+[7-3(4-2*3)div5]

$$( 7 ) ^ { 3 } + [ 7 - 3 ( 4 - 2 \cdot 3 ) \div 5 ]$$

Evaluate

$$\frac{1756}{5}=351.2$$

Solution Steps

Calculate 7 to the power of 3 and get 343.

$$343+7-\frac{3\left(4-2\times 3\right)}{5}$$

Add 343 and 7 to get 350.

$$350-\frac{3\left(4-2\times 3\right)}{5}$$

Multiply 2 and 3 to get 6.

$$350-\frac{3\left(4-6\right)}{5}$$

Subtract 6 from 4 to get -2.

$$350-\frac{3\left(-2\right)}{5}$$

Multiply 3 and -2 to get -6.

$$350-\frac{-6}{5}$$

Fraction \frac{-6}{5} can be rewritten as -\frac{6}{5} by extracting the negative sign.

$$350-\left(-\frac{6}{5}\right)$$

The opposite of -\frac{6}{5} is \frac{6}{5}.

$$350+\frac{6}{5}$$

Convert 350 to fraction \frac{1750}{5}.

$$\frac{1750}{5}+\frac{6}{5}$$

Since \frac{1750}{5} and \frac{6}{5} have the same denominator, add them by adding their numerators.

$$\frac{1750+6}{5}$$

Add 1750 and 6 to get 1756.

$$\frac{1756}{5}$$

Factor

$$\frac{2 ^ {2} \cdot 439}{5} = 351\frac{1}{5} = 351.2$$