Solve (73/20-(9/20)+73/20

$$( 7 \frac { 3 } { 20 } - ( \frac { 9 } { 20 } ) + 7 \frac { 3 } { 20 }$$

Evaluate

$$\frac{277}{20}=13.85$$

Solution Steps

Multiply 7 and 20 to get 140.

$$\frac{140+3}{20}-\frac{9}{20}+\frac{7\times 20+3}{20}$$

Add 140 and 3 to get 143.

$$\frac{143}{20}-\frac{9}{20}+\frac{7\times 20+3}{20}$$

Since \frac{143}{20} and \frac{9}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{143-9}{20}+\frac{7\times 20+3}{20}$$

Subtract 9 from 143 to get 134.

$$\frac{134}{20}+\frac{7\times 20+3}{20}$$

Reduce the fraction \frac{134}{20} to lowest terms by extracting and canceling out 2.

$$\frac{67}{10}+\frac{7\times 20+3}{20}$$

Multiply 7 and 20 to get 140.

$$\frac{67}{10}+\frac{140+3}{20}$$

Add 140 and 3 to get 143.

$$\frac{67}{10}+\frac{143}{20}$$

Least common multiple of 10 and 20 is 20. Convert \frac{67}{10} and \frac{143}{20} to fractions with denominator 20.

$$\frac{134}{20}+\frac{143}{20}$$

Since \frac{134}{20} and \frac{143}{20} have the same denominator, add them by adding their numerators.

$$\frac{134+143}{20}$$

Add 134 and 143 to get 277.

$$\frac{277}{20}$$

Factor

$$\frac{277}{2 ^ {2} \cdot 5} = 13\frac{17}{20} = 13.85$$