Solve (7/-2)+(-2/3)+(11/-6)=

$$( 7 / - 2 ) + ( - 2 / 3 ) + ( 11 / - 6 ) =$$

Evaluate

$$-6$$

Solution Steps

Fraction \frac{7}{-2} can be rewritten as -\frac{7}{2} by extracting the negative sign.

$$-\frac{7}{2}-\frac{2}{3}+\frac{11}{-6}$$

Least common multiple of 2 and 3 is 6. Convert -\frac{7}{2} and \frac{2}{3} to fractions with denominator 6.

$$-\frac{21}{6}-\frac{4}{6}+\frac{11}{-6}$$

Since -\frac{21}{6} and \frac{4}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-21-4}{6}+\frac{11}{-6}$$

Subtract 4 from -21 to get -25.

$$-\frac{25}{6}+\frac{11}{-6}$$

Fraction \frac{11}{-6} can be rewritten as -\frac{11}{6} by extracting the negative sign.

$$-\frac{25}{6}-\frac{11}{6}$$

Since -\frac{25}{6} and \frac{11}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-25-11}{6}$$

Subtract 11 from -25 to get -36.

$$\frac{-36}{6}$$

Divide -36 by 6 to get -6.

$$-6$$

Factor

$$-6$$