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\left(7+i\sqrt{10}\right)^{2}
Multiply 7+i\sqrt{10} and 7+i\sqrt{10} to get \left(7+i\sqrt{10}\right)^{2}.
49+14i\sqrt{10}-\left(\sqrt{10}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(7+i\sqrt{10}\right)^{2}.
49+14i\sqrt{10}-10
The square of \sqrt{10} is 10.
39+14i\sqrt{10}
Subtract 10 from 49 to get 39.