Solve (7+4)2+(3+4)^2+frac{sqrt{49}}{7}

$$( 7 + 4 ) 2 + ( 3 + 4 ) ^ { 2 } + \frac { \sqrt { 49 } } { 7 }$$

Evaluate

$$72$$

Solution Steps

Add 7 and 4 to get 11.

$$11\times 2+\left(3+4\right)^{2}+\frac{\sqrt{49}}{7}$$

Multiply 11 and 2 to get 22.

$$22+\left(3+4\right)^{2}+\frac{\sqrt{49}}{7}$$

Add 3 and 4 to get 7.

$$22+7^{2}+\frac{\sqrt{49}}{7}$$

Calculate 7 to the power of 2 and get 49.

$$22+49+\frac{\sqrt{49}}{7}$$

Add 22 and 49 to get 71.

$$71+\frac{\sqrt{49}}{7}$$

Calculate the square root of 49 and get 7.

$$71+\frac{7}{7}$$

Divide 7 by 7 to get 1.

$$71+1$$

Add 71 and 1 to get 72.

$$72$$

Factor

$$2^{3}\times 3^{2}$$