Solve (7+3)^2=7^2+2*7*3+3^2

$$( 7 + 3 ) ^ { 2 } = 7 ^ { 2 } + 2 \times 7 \times 3 + 3 ^ { 2 }$$

Verify

Solution Steps

Add 7 and 3 to get 10.

$$10^{2}=7^{2}+2\times 7\times 3+3^{2}$$

Calculate 10 to the power of 2 and get 100.

$$100=7^{2}+2\times 7\times 3+3^{2}$$

Calculate 7 to the power of 2 and get 49.

$$100=49+2\times 7\times 3+3^{2}$$

Multiply 2 and 7 to get 14.

$$100=49+14\times 3+3^{2}$$

Multiply 14 and 3 to get 42.

$$100=49+42+3^{2}$$

Add 49 and 42 to get 91.

$$100=91+3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$100=91+9$$

Add 91 and 9 to get 100.

$$100=100$$

Compare 100 and 100.

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