Solve (7+31/8)+(14+61/4

$$( 7 + 3 \frac { 1 } { 8 } ) + ( 14 + 6 \frac { 1 } { 4 }$$

Evaluate

$$\frac{243}{8}=30.375$$

Solution Steps

Multiply 3 and 8 to get 24.

$$7+\frac{24+1}{8}+14+\frac{6\times 4+1}{4}$$

Add 24 and 1 to get 25.

$$7+\frac{25}{8}+14+\frac{6\times 4+1}{4}$$

Convert 7 to fraction \frac{56}{8}.

$$\frac{56}{8}+\frac{25}{8}+14+\frac{6\times 4+1}{4}$$

Since \frac{56}{8} and \frac{25}{8} have the same denominator, add them by adding their numerators.

$$\frac{56+25}{8}+14+\frac{6\times 4+1}{4}$$

Add 56 and 25 to get 81.

$$\frac{81}{8}+14+\frac{6\times 4+1}{4}$$

Convert 14 to fraction \frac{112}{8}.

$$\frac{81}{8}+\frac{112}{8}+\frac{6\times 4+1}{4}$$

Since \frac{81}{8} and \frac{112}{8} have the same denominator, add them by adding their numerators.

$$\frac{81+112}{8}+\frac{6\times 4+1}{4}$$

Add 81 and 112 to get 193.

$$\frac{193}{8}+\frac{6\times 4+1}{4}$$

Multiply 6 and 4 to get 24.

$$\frac{193}{8}+\frac{24+1}{4}$$

Add 24 and 1 to get 25.

$$\frac{193}{8}+\frac{25}{4}$$

Least common multiple of 8 and 4 is 8. Convert \frac{193}{8} and \frac{25}{4} to fractions with denominator 8.

$$\frac{193}{8}+\frac{50}{8}$$

Since \frac{193}{8} and \frac{50}{8} have the same denominator, add them by adding their numerators.

$$\frac{193+50}{8}$$

Add 193 and 50 to get 243.

$$\frac{243}{8}$$

Factor

$$\frac{3 ^ {5}}{2 ^ {3}} = 30\frac{3}{8} = 30.375$$