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49+14\sqrt{6}+\left(\sqrt{6}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(7+\sqrt{6}\right)^{2}.
49+14\sqrt{6}+6
The square of \sqrt{6} is 6.
55+14\sqrt{6}
Add 49 and 6 to get 55.
49+14\sqrt{6}+\left(\sqrt{6}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(7+\sqrt{6}\right)^{2}.
49+14\sqrt{6}+6
The square of \sqrt{6} is 6.
55+14\sqrt{6}
Add 49 and 6 to get 55.