Solve (675+(-45)*12/8)*(-11/8)^3

$$( 675 + ( - 45 ) \cdot 1 \frac { 2 } { 8 } ) \cdot ( - 1 \frac { 1 } { 8 } ) ^ { 3 }$$

Evaluate

$$-\frac{1804275}{2048}=-880.993652344$$

Solution Steps

Multiply 1 and 8 to get 8.

$$\left(675-45\times \frac{8+2}{8}\right)\left(-\frac{1\times 8+1}{8}\right)^{3}$$

Add 8 and 2 to get 10.

$$\left(675-45\times \frac{10}{8}\right)\left(-\frac{1\times 8+1}{8}\right)^{3}$$

Reduce the fraction \frac{10}{8} to lowest terms by extracting and canceling out 2.

$$\left(675-45\times \frac{5}{4}\right)\left(-\frac{1\times 8+1}{8}\right)^{3}$$

Multiply -45 and \frac{5}{4} to get -\frac{225}{4}.

$$\left(675-\frac{225}{4}\right)\left(-\frac{1\times 8+1}{8}\right)^{3}$$

Subtract \frac{225}{4} from 675 to get \frac{2475}{4}.

$$\frac{2475}{4}\left(-\frac{1\times 8+1}{8}\right)^{3}$$

Multiply 1 and 8 to get 8.

$$\frac{2475}{4}\left(-\frac{8+1}{8}\right)^{3}$$

Add 8 and 1 to get 9.

$$\frac{2475}{4}\left(-\frac{9}{8}\right)^{3}$$

Calculate -\frac{9}{8} to the power of 3 and get -\frac{729}{512}.

$$\frac{2475}{4}\left(-\frac{729}{512}\right)$$

Multiply \frac{2475}{4} and -\frac{729}{512} to get -\frac{1804275}{2048}.

$$-\frac{1804275}{2048}$$

Factor

$$-\frac{1804275}{2048} = -880\frac{2035}{2048} = -880.99365234375$$