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\left(8x^{3}-3y^{6}\right)\left(8x^{3}+3y^{6}\right)
Rewrite 64x^{6}-9y^{12} as \left(8x^{3}\right)^{2}-\left(3y^{6}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).