Solve (62-54)^2+6^2-4+3*(8+10div2)+sqrt{25}+32*2div4+3

$$( 62 - 54 ) ^ { 2 } + 6 ^ { 2 } - 4 + 3 \times ( 8 + 10 \div 2 ) + \sqrt { 25 } + 32 \times 2 \div 4 + 3$$

Evaluate

$$159$$

Solution Steps

Subtract 54 from 62 to get 8.

$$8^{2}+6^{2}-4+3\left(8+\frac{10}{2}\right)+\sqrt{25}+\frac{32\times 2}{4}+3$$

Calculate 8 to the power of 2 and get 64.

$$64+6^{2}-4+3\left(8+\frac{10}{2}\right)+\sqrt{25}+\frac{32\times 2}{4}+3$$

Calculate 6 to the power of 2 and get 36.

$$64+36-4+3\left(8+\frac{10}{2}\right)+\sqrt{25}+\frac{32\times 2}{4}+3$$

Add 64 and 36 to get 100.

$$100-4+3\left(8+\frac{10}{2}\right)+\sqrt{25}+\frac{32\times 2}{4}+3$$

Subtract 4 from 100 to get 96.

$$96+3\left(8+\frac{10}{2}\right)+\sqrt{25}+\frac{32\times 2}{4}+3$$

Divide 10 by 2 to get 5.

$$96+3\left(8+5\right)+\sqrt{25}+\frac{32\times 2}{4}+3$$

Add 8 and 5 to get 13.

$$96+3\times 13+\sqrt{25}+\frac{32\times 2}{4}+3$$

Multiply 3 and 13 to get 39.

$$96+39+\sqrt{25}+\frac{32\times 2}{4}+3$$

Add 96 and 39 to get 135.

$$135+\sqrt{25}+\frac{32\times 2}{4}+3$$

Calculate the square root of 25 and get 5.

$$135+5+\frac{32\times 2}{4}+3$$

Add 135 and 5 to get 140.

$$140+\frac{32\times 2}{4}+3$$

Multiply 32 and 2 to get 64.

$$140+\frac{64}{4}+3$$

Divide 64 by 4 to get 16.

$$140+16+3$$

Add 140 and 16 to get 156.

$$156+3$$

Add 156 and 3 to get 159.

$$159$$

Factor

$$3\times 53$$