Solve (615+4180*25*10^-1)*(228-243)/(704*10^-2*(243-539))

$$( 615 + 4180 \times 25 \times 10 ^ { - 1 } ) \times ( 228 - 243 ) / ( 704 \times 10 ^ { - 2 } \times ( 243 - 539 ) )$$

Evaluate

$$\frac{4149375}{52096}\approx 79.648629453$$

Solution Steps

Multiply 4180 and 25 to get 104500.

$$\frac{\left(615+104500\times 10^{-1}\right)\left(228-243\right)}{704\times 10^{-2}\left(243-539\right)}$$

Calculate 10 to the power of -1 and get \frac{1}{10}.

$$\frac{\left(615+104500\times \frac{1}{10}\right)\left(228-243\right)}{704\times 10^{-2}\left(243-539\right)}$$

Multiply 104500 and \frac{1}{10} to get 10450.

$$\frac{\left(615+10450\right)\left(228-243\right)}{704\times 10^{-2}\left(243-539\right)}$$

Add 615 and 10450 to get 11065.

$$\frac{11065\left(228-243\right)}{704\times 10^{-2}\left(243-539\right)}$$

Subtract 243 from 228 to get -15.

$$\frac{11065\left(-15\right)}{704\times 10^{-2}\left(243-539\right)}$$

Multiply 11065 and -15 to get -165975.

$$\frac{-165975}{704\times 10^{-2}\left(243-539\right)}$$

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$\frac{-165975}{704\times \frac{1}{100}\left(243-539\right)}$$

Multiply 704 and \frac{1}{100} to get \frac{176}{25}.

$$\frac{-165975}{\frac{176}{25}\left(243-539\right)}$$

Subtract 539 from 243 to get -296.

$$\frac{-165975}{\frac{176}{25}\left(-296\right)}$$

Multiply \frac{176}{25} and -296 to get -\frac{52096}{25}.

$$\frac{-165975}{-\frac{52096}{25}}$$

Divide -165975 by -\frac{52096}{25} by multiplying -165975 by the reciprocal of -\frac{52096}{25}.

$$-165975\left(-\frac{25}{52096}\right)$$

Multiply -165975 and -\frac{25}{52096} to get \frac{4149375}{52096}.

$$\frac{4149375}{52096}$$

Factor

$$\frac{3 \cdot 5 ^ {4} \cdot 2213}{2 ^ {7} \cdot 11 \cdot 37} = 79\frac{33791}{52096} = 79.64862945331696$$