Solve (61,5+4180*2,5*10^-1)*(22,8-24,3)/(7,04*10^-2*(24,3-53,9))

$$( 61,5 + 4180 \times 2,5 \times 10 ^ { - 1 } ) \times ( 22,8 - 24,3 ) / ( 7,04 \times 10 ^ { - 2 } \times ( 24,3 - 53,9 ) )$$

Evaluate

$$\frac{20746875}{26048}\approx 796,486294533$$

Solution Steps

Multiply 4180 and 2,5 to get 10450.

$$\frac{\left(61,5+10450\times 10^{-1}\right)\left(22,8-24,3\right)}{7,04\times 10^{-2}\left(24,3-53,9\right)}$$

Calculate 10 to the power of -1 and get \frac{1}{10}.

$$\frac{\left(61,5+10450\times \frac{1}{10}\right)\left(22,8-24,3\right)}{7,04\times 10^{-2}\left(24,3-53,9\right)}$$

Multiply 10450 and \frac{1}{10} to get 1045.

$$\frac{\left(61,5+1045\right)\left(22,8-24,3\right)}{7,04\times 10^{-2}\left(24,3-53,9\right)}$$

Add 61,5 and 1045 to get 1106,5.

$$\frac{1106,5\left(22,8-24,3\right)}{7,04\times 10^{-2}\left(24,3-53,9\right)}$$

Subtract 24,3 from 22,8 to get -1,5.

$$\frac{1106,5\left(-1,5\right)}{7,04\times 10^{-2}\left(24,3-53,9\right)}$$

Multiply 1106,5 and -1,5 to get -1659,75.

$$\frac{-1659,75}{7,04\times 10^{-2}\left(24,3-53,9\right)}$$

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$\frac{-1659,75}{7,04\times \frac{1}{100}\left(24,3-53,9\right)}$$

Multiply 7,04 and \frac{1}{100} to get \frac{44}{625}.

$$\frac{-1659,75}{\frac{44}{625}\left(24,3-53,9\right)}$$

Subtract 53,9 from 24,3 to get -29,6.

$$\frac{-1659,75}{\frac{44}{625}\left(-29,6\right)}$$

Multiply \frac{44}{625} and -29,6 to get -\frac{6512}{3125}.

$$\frac{-1659,75}{-\frac{6512}{3125}}$$

Divide -1659,75 by -\frac{6512}{3125} by multiplying -1659,75 by the reciprocal of -\frac{6512}{3125}.

$$-1659,75\left(-\frac{3125}{6512}\right)$$

Multiply -1659,75 and -\frac{3125}{6512} to get \frac{20746875}{26048}.

$$\frac{20746875}{26048}$$

Factor

$$\frac{3 \cdot 2213 \cdot 5 ^ {5}}{11 \cdot 37 \cdot 2 ^ {6}} = 796\frac{12667}{26048} = 796.4862945331695$$