Solve (6000x10^-6+0,3x0,5)=0,156

$$( 6000 x 10 ^ { - 6 } + 0,3 x 0,5 ) = 0,156$$

Solve for x

$$x=26-25x_{0}$$

Steps for Solving Linear Equation

Calculate 10 to the power of -6 and get \frac{1}{1000000}.

$$6000x\times \frac{1}{1000000}+0,3x_{0}\times 0,5=0,156$$

Multiply 6000 and \frac{1}{1000000} to get \frac{3}{500}.

$$\frac{3}{500}x+0,3x_{0}\times 0,5=0,156$$

Multiply 0,3 and 0,5 to get 0,15.

$$\frac{3}{500}x+0,15x_{0}=0,156$$

Subtract 0,15x_{0} from both sides.

$$\frac{3}{500}x=0,156-0,15x_{0}$$

The equation is in standard form.

$$\frac{3}{500}x=-\frac{3x_{0}}{20}+0,156$$

Divide both sides of the equation by \frac{3}{500}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{500}x}{\frac{3}{500}}=\frac{-\frac{3x_{0}}{20}+0,156}{\frac{3}{500}}$$

Dividing by \frac{3}{500} undoes the multiplication by \frac{3}{500}.

$$x=\frac{-\frac{3x_{0}}{20}+0,156}{\frac{3}{500}}$$

Divide 0,156-\frac{3x_{0}}{20} by \frac{3}{500} by multiplying 0,156-\frac{3x_{0}}{20} by the reciprocal of \frac{3}{500}.

$$x=26-25x_{0}$$

Solve for x_0

$$x_{0}=\frac{26-x}{25}$$

Steps for Solving Linear Equation

Calculate 10 to the power of -6 and get \frac{1}{1000000}.

$$6000x\times \frac{1}{1000000}+0,3x_{0}\times 0,5=0,156$$

Multiply 6000 and \frac{1}{1000000} to get \frac{3}{500}.

$$\frac{3}{500}x+0,3x_{0}\times 0,5=0,156$$

Multiply 0,3 and 0,5 to get 0,15.

$$\frac{3}{500}x+0,15x_{0}=0,156$$

Subtract \frac{3}{500}x from both sides.

$$0,15x_{0}=0,156-\frac{3}{500}x$$

The equation is in standard form.

$$0,15x_{0}=-\frac{3x}{500}+0,156$$

Divide both sides of the equation by 0,15, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{0,15x_{0}}{0,15}=\frac{-\frac{3x}{500}+\frac{39}{250}}{0,15}$$

Dividing by 0,15 undoes the multiplication by 0,15.

$$x_{0}=\frac{-\frac{3x}{500}+\frac{39}{250}}{0,15}$$

Divide \frac{39}{250}-\frac{3x}{500} by 0,15 by multiplying \frac{39}{250}-\frac{3x}{500} by the reciprocal of 0,15.

$$x_{0}=\frac{26-x}{25}$$