Solve for x
x=-\frac{2}{y}
y\neq 0
Solve for y
y=-\frac{2}{x}
x\neq 0
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36x^{2}-12xy+y^{2}-\left(6x+y\right)^{2}=48
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(6x-y\right)^{2}.
36x^{2}-12xy+y^{2}-\left(36x^{2}+12xy+y^{2}\right)=48
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(6x+y\right)^{2}.
36x^{2}-12xy+y^{2}-36x^{2}-12xy-y^{2}=48
To find the opposite of 36x^{2}+12xy+y^{2}, find the opposite of each term.
-12xy+y^{2}-12xy-y^{2}=48
Combine 36x^{2} and -36x^{2} to get 0.
-24xy+y^{2}-y^{2}=48
Combine -12xy and -12xy to get -24xy.
-24xy=48
Combine y^{2} and -y^{2} to get 0.
\left(-24y\right)x=48
The equation is in standard form.
\frac{\left(-24y\right)x}{-24y}=\frac{48}{-24y}
Divide both sides by -24y.
x=\frac{48}{-24y}
Dividing by -24y undoes the multiplication by -24y.
x=-\frac{2}{y}
Divide 48 by -24y.
36x^{2}-12xy+y^{2}-\left(6x+y\right)^{2}=48
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(6x-y\right)^{2}.
36x^{2}-12xy+y^{2}-\left(36x^{2}+12xy+y^{2}\right)=48
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(6x+y\right)^{2}.
36x^{2}-12xy+y^{2}-36x^{2}-12xy-y^{2}=48
To find the opposite of 36x^{2}+12xy+y^{2}, find the opposite of each term.
-12xy+y^{2}-12xy-y^{2}=48
Combine 36x^{2} and -36x^{2} to get 0.
-24xy+y^{2}-y^{2}=48
Combine -12xy and -12xy to get -24xy.
-24xy=48
Combine y^{2} and -y^{2} to get 0.
\left(-24x\right)y=48
The equation is in standard form.
\frac{\left(-24x\right)y}{-24x}=\frac{48}{-24x}
Divide both sides by -24x.
y=\frac{48}{-24x}
Dividing by -24x undoes the multiplication by -24x.
y=-\frac{2}{x}
Divide 48 by -24x.
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