Solve (6r+1-2r^3)-(4r^4+2r)-(3r+2)

$$( 6 r + 1 - 2 r ^ { 3 } ) - ( 4 r ^ { 4 } + 2 r ) - ( 3 r + 2 )$$

Evaluate

$$-4r^{4}-2r^{3}+r-1$$

Solution Steps

To find the opposite of 4r^{4}+2r, find the opposite of each term.

$$6r+1-2r^{3}-4r^{4}-2r-\left(3r+2\right)$$

Combine 6r and -2r to get 4r.

$$4r+1-2r^{3}-4r^{4}-\left(3r+2\right)$$

To find the opposite of 3r+2, find the opposite of each term.

$$4r+1-2r^{3}-4r^{4}-3r-2$$

Combine 4r and -3r to get r.

$$r+1-2r^{3}-4r^{4}-2$$

Subtract 2 from 1 to get -1.

$$r-1-2r^{3}-4r^{4}$$

Expand

$$-4r^{4}-2r^{3}+r-1$$

Solution Steps

To find the opposite of 4r^{4}+2r, find the opposite of each term.

$$6r+1-2r^{3}-4r^{4}-2r-\left(3r+2\right)$$

Combine 6r and -2r to get 4r.

$$4r+1-2r^{3}-4r^{4}-\left(3r+2\right)$$

To find the opposite of 3r+2, find the opposite of each term.

$$4r+1-2r^{3}-4r^{4}-3r-2$$

Combine 4r and -3r to get r.

$$r+1-2r^{3}-4r^{4}-2$$

Subtract 2 from 1 to get -1.

$$r-1-2r^{3}-4r^{4}$$