Solve (6a^2-7)^2=

$$( 6 a ^ { 2 } - 7 ) ^ { 2 } =$$

Evaluate

$$\left(6a^{2}-7\right)^{2}$$

Solution Steps

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(6a^{2}-7\right)^{2}.

$$36\left(a^{2}\right)^{2}-84a^{2}+49$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$36a^{4}-84a^{2}+49$$

Expand

$$36a^{4}-84a^{2}+49$$

Solution Steps

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(6a^{2}-7\right)^{2}.

$$36\left(a^{2}\right)^{2}-84a^{2}+49$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$36a^{4}-84a^{2}+49$$