Solve (6-4)*8+5-3*(-2-1)-(13-3):5

$$( 6 - 4 ) \cdot 8 + 5 - 3 \cdot ( - 2 - 1 ) - ( 13 - 3 ) : 5$$

Evaluate

$$28$$

Solution Steps

Subtract 4 from 6 to get 2.

$$2\times 8+5-3\left(-2-1\right)-\frac{13-3}{5}$$

Multiply 2 and 8 to get 16.

$$16+5-3\left(-2-1\right)-\frac{13-3}{5}$$

Add 16 and 5 to get 21.

$$21-3\left(-2-1\right)-\frac{13-3}{5}$$

Subtract 1 from -2 to get -3.

$$21-3\left(-3\right)-\frac{13-3}{5}$$

Multiply 3 and -3 to get -9.

$$21-\left(-9\right)-\frac{13-3}{5}$$

The opposite of -9 is 9.

$$21+9-\frac{13-3}{5}$$

Add 21 and 9 to get 30.

$$30-\frac{13-3}{5}$$

Subtract 3 from 13 to get 10.

$$30-\frac{10}{5}$$

Divide 10 by 5 to get 2.

$$30-2$$

Subtract 2 from 30 to get 28.

$$28$$

Factor

$$2^{2}\times 7$$