Solve (6-14+9/8)^2+(4-42+9/8+14)^2=160

$$( 6 - \frac { 14 + 9 } { 8 } ) ^ { 2 } + ( 4 - \frac { 42 + 9 } { 8 } + 14 ) ^ { 2 } = 160$$

Verify

Solution Steps

Add 14 and 9 to get 23.

$$\left(6-\frac{23}{8}\right)^{2}+\left(4-\frac{42+9}{8}+14\right)^{2}=160$$

Subtract \frac{23}{8} from 6 to get \frac{25}{8}.

$$\left(\frac{25}{8}\right)^{2}+\left(4-\frac{42+9}{8}+14\right)^{2}=160$$

Calculate \frac{25}{8} to the power of 2 and get \frac{625}{64}.

$$\frac{625}{64}+\left(4-\frac{42+9}{8}+14\right)^{2}=160$$

Add 42 and 9 to get 51.

$$\frac{625}{64}+\left(4-\frac{51}{8}+14\right)^{2}=160$$

Subtract \frac{51}{8} from 4 to get -\frac{19}{8}.

$$\frac{625}{64}+\left(-\frac{19}{8}+14\right)^{2}=160$$

Add -\frac{19}{8} and 14 to get \frac{93}{8}.

$$\frac{625}{64}+\left(\frac{93}{8}\right)^{2}=160$$

Calculate \frac{93}{8} to the power of 2 and get \frac{8649}{64}.

$$\frac{625}{64}+\frac{8649}{64}=160$$

Add \frac{625}{64} and \frac{8649}{64} to get \frac{4637}{32}.

$$\frac{4637}{32}=160$$

Convert 160 to fraction \frac{5120}{32}.

$$\frac{4637}{32}=\frac{5120}{32}$$

Compare \frac{4637}{32} and \frac{5120}{32}.

$$\text{false}$$