Solve (6sqrt{10})^2=x+3x

$$( 6 \sqrt { 10 } ) ^ { 2 } = x + 3 x$$

Solve for x

$$x=90$$

Steps for Solving Linear Equation

Expand \left(6\sqrt{10}\right)^{2}.

$$6^{2}\left(\sqrt{10}\right)^{2}=x+3x$$

Calculate 6 to the power of 2 and get 36.

$$36\left(\sqrt{10}\right)^{2}=x+3x$$

The square of \sqrt{10} is 10.

$$36\times 10=x+3x$$

Multiply 36 and 10 to get 360.

$$360=x+3x$$

Combine x and 3x to get 4x.

$$360=4x$$

Swap sides so that all variable terms are on the left hand side.

$$4x=360$$

Divide both sides by 4.

$$x=\frac{360}{4}$$

Divide 360 by 4 to get 90.

$$x=90$$