Solve (6*2^-2-3*2^-1):(7/10)^-2=

$$( 6 \cdot 2 ^ { - 2 } - 3 \cdot 2 ^ { - 1 } ) : ( \frac { 7 } { 10 } ) ^ { - 2 } =$$

Evaluate

$$0$$

Solution Steps

Calculate 2 to the power of -2 and get \frac{1}{4}.

$$\frac{6\times \frac{1}{4}-3\times 2^{-1}}{\left(\frac{7}{10}\right)^{-2}}$$

Multiply 6 and \frac{1}{4} to get \frac{3}{2}.

$$\frac{\frac{3}{2}-3\times 2^{-1}}{\left(\frac{7}{10}\right)^{-2}}$$

Calculate 2 to the power of -1 and get \frac{1}{2}.

$$\frac{\frac{3}{2}-3\times \frac{1}{2}}{\left(\frac{7}{10}\right)^{-2}}$$

Multiply 3 and \frac{1}{2} to get \frac{3}{2}.

$$\frac{\frac{3}{2}-\frac{3}{2}}{\left(\frac{7}{10}\right)^{-2}}$$

Subtract \frac{3}{2} from \frac{3}{2} to get 0.

$$\frac{0}{\left(\frac{7}{10}\right)^{-2}}$$

Calculate \frac{7}{10} to the power of -2 and get \frac{100}{49}.

$$\frac{0}{\frac{100}{49}}$$

Zero divided by any non-zero number gives zero.

$$0$$

Factor

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