Solve (6^{-2}*6^5*6^0*6^4)^2=

$$( 6 ^ { - 2 } \cdot 6 ^ { 5 } \cdot 6 ^ { 0 } \cdot 6 ^ { 4 } ) ^ { 2 } =$$

Evaluate

$$78364164096$$

Solution Steps

To multiply powers of the same base, add their exponents. Add -2 and 5 to get 3.

$$\left(6^{3}\times 6^{0}\times 6^{4}\right)^{2}$$

To multiply powers of the same base, add their exponents. Add 3 and 0 to get 3.

$$\left(6^{3}\times 6^{4}\right)^{2}$$

To multiply powers of the same base, add their exponents. Add 3 and 4 to get 7.

$$\left(6^{7}\right)^{2}$$

Calculate 6 to the power of 7 and get 279936.

$$279936^{2}$$

Calculate 279936 to the power of 2 and get 78364164096.

$$78364164096$$

Factor

$$2^{14}\times 3^{14}$$