Solve (6^-1-8^-1)+(2-(3^-1)^2)?

$$( 6 ^ { - 1 } - 8 ^ { - 1 } ) + ( 2 - ( 3 ^ { - 1 } ) ^ { 2 } ) ?$$

Evaluate

$$\frac{139}{72}\approx 1.930555556$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply -1 and 2 to get -2.

$$6^{-1}-8^{-1}+2-3^{-2}$$

Calculate 6 to the power of -1 and get \frac{1}{6}.

$$\frac{1}{6}-8^{-1}+2-3^{-2}$$

Calculate 8 to the power of -1 and get \frac{1}{8}.

$$\frac{1}{6}-\frac{1}{8}+2-3^{-2}$$

Subtract \frac{1}{8} from \frac{1}{6} to get \frac{1}{24}.

$$\frac{1}{24}+2-3^{-2}$$

Calculate 3 to the power of -2 and get \frac{1}{9}.

$$\frac{1}{24}+2-\frac{1}{9}$$

Subtract \frac{1}{9} from 2 to get \frac{17}{9}.

$$\frac{1}{24}+\frac{17}{9}$$

Add \frac{1}{24} and \frac{17}{9} to get \frac{139}{72}.

$$\frac{139}{72}$$

Factor

$$\frac{139}{2 ^ {3} \cdot 3 ^ {2}} = 1\frac{67}{72} = 1.9305555555555556$$