Solve (6+sqrt{35})-(sqrt{3}i-3)+(-5-2sqrt{3}i)

$$( 6 + \sqrt { 35 } ) - ( \sqrt { 3 } i - 3 ) + ( - 5 - 2 \sqrt { 3 } i )$$

Evaluate

$$-3\sqrt{3}i+\sqrt{35}+4\approx 9.916079783-5.196152423i$$

Solution Steps

To find the opposite of i\sqrt{3}-3, find the opposite of each term.

$$6+\sqrt{35}-i\sqrt{3}-\left(-3\right)+-5-2i\sqrt{3}$$

The opposite of -3 is 3.

$$6+\sqrt{35}-i\sqrt{3}+3+-5-2i\sqrt{3}$$

Add 6 and 3 to get 9.

$$9+\sqrt{35}-i\sqrt{3}+-5-2i\sqrt{3}$$

Subtract 5 from 9 to get 4.

$$4+\sqrt{35}-i\sqrt{3}-2i\sqrt{3}$$

Combine -i\sqrt{3} and -2i\sqrt{3} to get -3i\sqrt{3}.

$$4+\sqrt{35}-3i\sqrt{3}$$

Real Part

$$\sqrt{35} + 4 = 9.916079783$$