Solve (5y+2)-(16/3y+1)=18

$$( 5 y + 2 ) - ( \frac { 16 } { 3 } y + 1 ) = 18$$

Solve for y

$$y=-51$$

Steps for Solving Linear Equation

To find the opposite of \frac{16}{3}y+1, find the opposite of each term.

$$5y+2-\frac{16}{3}y-1=18$$

Combine 5y and -\frac{16}{3}y to get -\frac{1}{3}y.

$$-\frac{1}{3}y+2-1=18$$

Subtract 1 from 2 to get 1.

$$-\frac{1}{3}y+1=18$$

Subtract 1 from both sides.

$$-\frac{1}{3}y=18-1$$

Subtract 1 from 18 to get 17.

$$-\frac{1}{3}y=17$$

Multiply both sides by -3, the reciprocal of -\frac{1}{3}.

$$y=17\left(-3\right)$$

Multiply 17 and -3 to get -51.

$$y=-51$$